-2[5-(2z+1)]-4=2(3-2)

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Solution for -2[5-(2z+1)]-4=2(3-2) equation:


Simplifying
-2[5 + -1(2z + 1)] + -4 = 2(3 + -2)

Reorder the terms:
-2[5 + -1(1 + 2z)] + -4 = 2(3 + -2)
-2[5 + (1 * -1 + 2z * -1)] + -4 = 2(3 + -2)
-2[5 + (-1 + -2z)] + -4 = 2(3 + -2)

Combine like terms: 5 + -1 = 4
-2[4 + -2z] + -4 = 2(3 + -2)
[4 * -2 + -2z * -2] + -4 = 2(3 + -2)
[-8 + 4z] + -4 = 2(3 + -2)

Reorder the terms:
-8 + -4 + 4z = 2(3 + -2)

Combine like terms: -8 + -4 = -12
-12 + 4z = 2(3 + -2)

Combine like terms: 3 + -2 = 1
-12 + 4z = 2(1)

Multiply 2 * 1
-12 + 4z = 2

Solving
-12 + 4z = 2

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 4z = 2 + 12

Combine like terms: -12 + 12 = 0
0 + 4z = 2 + 12
4z = 2 + 12

Combine like terms: 2 + 12 = 14
4z = 14

Divide each side by '4'.
z = 3.5

Simplifying
z = 3.5

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